Integrand size = 26, antiderivative size = 60 \[ \int \cos ^4(c+d x) (a \cos (c+d x)+b \sin (c+d x)) \, dx=-\frac {b \cos ^5(c+d x)}{5 d}+\frac {a \sin (c+d x)}{d}-\frac {2 a \sin ^3(c+d x)}{3 d}+\frac {a \sin ^5(c+d x)}{5 d} \]
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Time = 0.08 (sec) , antiderivative size = 60, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {3169, 2713, 2645, 30} \[ \int \cos ^4(c+d x) (a \cos (c+d x)+b \sin (c+d x)) \, dx=\frac {a \sin ^5(c+d x)}{5 d}-\frac {2 a \sin ^3(c+d x)}{3 d}+\frac {a \sin (c+d x)}{d}-\frac {b \cos ^5(c+d x)}{5 d} \]
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Rule 30
Rule 2645
Rule 2713
Rule 3169
Rubi steps \begin{align*} \text {integral}& = \int \left (a \cos ^5(c+d x)+b \cos ^4(c+d x) \sin (c+d x)\right ) \, dx \\ & = a \int \cos ^5(c+d x) \, dx+b \int \cos ^4(c+d x) \sin (c+d x) \, dx \\ & = -\frac {a \text {Subst}\left (\int \left (1-2 x^2+x^4\right ) \, dx,x,-\sin (c+d x)\right )}{d}-\frac {b \text {Subst}\left (\int x^4 \, dx,x,\cos (c+d x)\right )}{d} \\ & = -\frac {b \cos ^5(c+d x)}{5 d}+\frac {a \sin (c+d x)}{d}-\frac {2 a \sin ^3(c+d x)}{3 d}+\frac {a \sin ^5(c+d x)}{5 d} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 60, normalized size of antiderivative = 1.00 \[ \int \cos ^4(c+d x) (a \cos (c+d x)+b \sin (c+d x)) \, dx=-\frac {b \cos ^5(c+d x)}{5 d}+\frac {a \sin (c+d x)}{d}-\frac {2 a \sin ^3(c+d x)}{3 d}+\frac {a \sin ^5(c+d x)}{5 d} \]
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Time = 0.69 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.77
method | result | size |
derivativedivides | \(\frac {\frac {a \left (\frac {8}{3}+\cos \left (d x +c \right )^{4}+\frac {4 \cos \left (d x +c \right )^{2}}{3}\right ) \sin \left (d x +c \right )}{5}-\frac {\cos \left (d x +c \right )^{5} b}{5}}{d}\) | \(46\) |
default | \(\frac {\frac {a \left (\frac {8}{3}+\cos \left (d x +c \right )^{4}+\frac {4 \cos \left (d x +c \right )^{2}}{3}\right ) \sin \left (d x +c \right )}{5}-\frac {\cos \left (d x +c \right )^{5} b}{5}}{d}\) | \(46\) |
parts | \(\frac {a \left (\frac {8}{3}+\cos \left (d x +c \right )^{4}+\frac {4 \cos \left (d x +c \right )^{2}}{3}\right ) \sin \left (d x +c \right )}{5 d}-\frac {b \cos \left (d x +c \right )^{5}}{5 d}\) | \(48\) |
risch | \(-\frac {b \cos \left (d x +c \right )}{8 d}+\frac {5 a \sin \left (d x +c \right )}{8 d}-\frac {b \cos \left (5 d x +5 c \right )}{80 d}+\frac {a \sin \left (5 d x +5 c \right )}{80 d}-\frac {b \cos \left (3 d x +3 c \right )}{16 d}+\frac {5 a \sin \left (3 d x +3 c \right )}{48 d}\) | \(86\) |
parallelrisch | \(\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{9}-2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{8} b +\frac {8 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{7}}{3}+\frac {116 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{15}-4 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4} b +\frac {8 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{3}+2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )-\frac {2 b}{5}}{d \left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{5}}\) | \(121\) |
norman | \(\frac {-\frac {2 b}{5 d}+\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{d}+\frac {8 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{3 d}+\frac {116 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{15 d}+\frac {8 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{7}}{3 d}+\frac {2 a \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{9}}{d}-\frac {4 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}{d}-\frac {2 b \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{8}}{d}}{\left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{5}}\) | \(141\) |
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Time = 0.26 (sec) , antiderivative size = 51, normalized size of antiderivative = 0.85 \[ \int \cos ^4(c+d x) (a \cos (c+d x)+b \sin (c+d x)) \, dx=-\frac {3 \, b \cos \left (d x + c\right )^{5} - {\left (3 \, a \cos \left (d x + c\right )^{4} + 4 \, a \cos \left (d x + c\right )^{2} + 8 \, a\right )} \sin \left (d x + c\right )}{15 \, d} \]
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Time = 0.23 (sec) , antiderivative size = 87, normalized size of antiderivative = 1.45 \[ \int \cos ^4(c+d x) (a \cos (c+d x)+b \sin (c+d x)) \, dx=\begin {cases} \frac {8 a \sin ^{5}{\left (c + d x \right )}}{15 d} + \frac {4 a \sin ^{3}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{3 d} + \frac {a \sin {\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{d} - \frac {b \cos ^{5}{\left (c + d x \right )}}{5 d} & \text {for}\: d \neq 0 \\x \left (a \cos {\left (c \right )} + b \sin {\left (c \right )}\right ) \cos ^{4}{\left (c \right )} & \text {otherwise} \end {cases} \]
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Time = 0.21 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.82 \[ \int \cos ^4(c+d x) (a \cos (c+d x)+b \sin (c+d x)) \, dx=-\frac {3 \, b \cos \left (d x + c\right )^{5} - {\left (3 \, \sin \left (d x + c\right )^{5} - 10 \, \sin \left (d x + c\right )^{3} + 15 \, \sin \left (d x + c\right )\right )} a}{15 \, d} \]
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Time = 0.29 (sec) , antiderivative size = 85, normalized size of antiderivative = 1.42 \[ \int \cos ^4(c+d x) (a \cos (c+d x)+b \sin (c+d x)) \, dx=-\frac {b \cos \left (5 \, d x + 5 \, c\right )}{80 \, d} - \frac {b \cos \left (3 \, d x + 3 \, c\right )}{16 \, d} - \frac {b \cos \left (d x + c\right )}{8 \, d} + \frac {a \sin \left (5 \, d x + 5 \, c\right )}{80 \, d} + \frac {5 \, a \sin \left (3 \, d x + 3 \, c\right )}{48 \, d} + \frac {5 \, a \sin \left (d x + c\right )}{8 \, d} \]
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Time = 22.66 (sec) , antiderivative size = 67, normalized size of antiderivative = 1.12 \[ \int \cos ^4(c+d x) (a \cos (c+d x)+b \sin (c+d x)) \, dx=\frac {8\,a\,\sin \left (c+d\,x\right )}{15\,d}-\frac {b\,{\cos \left (c+d\,x\right )}^5}{5\,d}+\frac {4\,a\,{\cos \left (c+d\,x\right )}^2\,\sin \left (c+d\,x\right )}{15\,d}+\frac {a\,{\cos \left (c+d\,x\right )}^4\,\sin \left (c+d\,x\right )}{5\,d} \]
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